Implementation of various algorithms
#define PROBLEM "https://yukicoder.me/problems/no/705"
#include "dd_monotone_minima.hpp"
// yukicoder No.705 ゴミ拾い Hard
/*
A, X, Y: N 個
これらを区間に分割していく
dp[j] = min_{0 ≦ i < j}(dp[i] + |A[j-1] - X[i]|^3 + |-Y[i]|^3)
i -> j のコスト:|A[j-1] - X[i]|^3 + |-Y[i]|^3 ...... 差の凸関数 (Monge) + 縞々 (Monge) -> Monge
スタート: 0, ゴール: N
*/
int main() {
int N;
cin >> N;
vector<long long> A(N), X(N), Y(N);
for (int i = 0; i < N; i++) cin >> A[i];
for (int i = 0; i < N; i++) cin >> X[i];
for (int i = 0; i < N; i++) cin >> Y[i];
auto func = [&](int i, int j) -> long long {
long long dx = abs(A[j-1] - X[i]), dy = abs(Y[i]);
return dx * dx * dx + dy * dy * dy;
};
DDMonotoneMinima<long long> opt;
auto res = opt.solve(N, func);
cout << res[N].first << endl;
}#line 1 "tests/yukicoder/yukicoder_0705_dd_monotone_minima.test.cpp"
#define PROBLEM "https://yukicoder.me/problems/no/705"
#line 2 "Optimization/dd_monotone_minima.hpp"
#include <bits/stdc++.h>
#line 4 "Optimization/dd_monotone_minima.hpp"
using namespace std;
#line 4 "Optimization/monotone_minima.hpp"
using namespace std;
// find min_j f(i, j) for all i, by Monotone Minima, O(H + W log H)
// f(i, j) must be monotone (argmin is not decreasing)
// slide access OK
template<class VAL, class FUNC> void MonotoneMinimaRec
(int HL, int HR, int WL, int WR, const FUNC &f, vector<pair<VAL, int>> &res) {
if (HR - HL <= 0) return;
int HM = (HL + HR) / 2;
res[HM].second = WL;
for (int i = WL; i < WR; i++) {
VAL val = f(HM, i);
if (res[HM].first > val) res[HM] = make_pair(val, i);
}
MonotoneMinimaRec(HL, HM, WL, res[HM].second + 1, f, res);
MonotoneMinimaRec(HM + 1, HR, res[HM].second, WR, f, res);
}
template<class VAL, class FUNC> vector<pair<VAL, int>> MonotoneMinima(int H, int W, const FUNC &f) {
vector<pair<VAL, int>> res(H, make_pair(numeric_limits<VAL>::max() / 2, -1));
MonotoneMinimaRec(0, H, 0, W, f, res);
return res;
}
#line 7 "Optimization/dd_monotone_minima.hpp"
// find shortest path on DAG by D&D Monotone Minima, O(N (log N)^2)
// vertex: 0, 1, 2, ..., N
// A(j, i) = dp[i] + f(i, j) must be monotone (argmin is not decreasing)
// Attention: Even if f is monotone, A is not necessarily monotone
// slide access OK
template<class VAL> struct DDMonotoneMinima {
VAL INF = numeric_limits<VAL>::max() / 2;
int CNT_INF = numeric_limits<int>::max() / 2;
// results
vector<VAL> dp;
vector<int> cnt, prev;
// solver (random access ver)
template<class FUNC> vector<pair<VAL, int>> solve(int N, const FUNC &f) {
dp.assign(N + 1, INF);
cnt.assign(N + 1, CNT_INF);
prev.assign(N + 1, 0);
dp[0] = 0, cnt[0] = 0;
vector<pair<VAL, int>> res(N + 1, make_pair(INF, -1));
vector<pair<VAL, int>> tmp(N + 1, make_pair(INF, -1));
res[0].first = VAL(0);
auto f2 = [&](int i, int j) -> VAL { return res[j].first + f(j, i); };
auto rec = [&](auto &&rec, int left, int right) -> void {
if (right - left <= 1) return;
int mid = (left + right) / 2;
rec(rec, left, mid);
for (int i = mid; i < right; i++) tmp[i] = {INF, -1};
MonotoneMinimaRec(mid, right, left, mid, f2, tmp);
for (int i = mid; i < right; i++) if (tmp[i].first < res[i].first) res[i] = tmp[i];
rec(rec, mid, right);
};
rec(rec, 0, N + 1);
for (int r = 1; r <= N; r++) {
dp[r] = res[r].first;
prev[r] = res[r].second;
if (prev[r] != -1) cnt[r] = cnt[prev[r]] + 1;
}
return res;
}
// solver (slide access ver)
template<class ADD, class DEL, class GETCOST> vector<pair<VAL, int>> solve
(int N, const ADD &add, const DEL &del, const GETCOST &get) {
int left = 0, right = 0;
auto f = [&](int i, int j) -> long long {
while (left < i) del(left++);
while (i < left) add(--left);
while (right < j) add(right++);
while (j < right) del(--right);
return get();
};
auto f2 = [&](int i, int j) -> VAL { return (j < i ? dp[j] + f(j, i) : INF); };
return solve(N, f2);
}
// reconstruct the shortest path
vector<int> reconstruct() {
int N = (int)dp.size() - 1;
vector<int> path;
for (int v = N; v > 0; v = prev[v]) path.emplace_back(v);
path.emplace_back(0);
reverse(path.begin(), path.end());
return path;
}
};
#line 4 "tests/yukicoder/yukicoder_0705_dd_monotone_minima.test.cpp"
// yukicoder No.705 ゴミ拾い Hard
/*
A, X, Y: N 個
これらを区間に分割していく
dp[j] = min_{0 ≦ i < j}(dp[i] + |A[j-1] - X[i]|^3 + |-Y[i]|^3)
i -> j のコスト:|A[j-1] - X[i]|^3 + |-Y[i]|^3 ...... 差の凸関数 (Monge) + 縞々 (Monge) -> Monge
スタート: 0, ゴール: N
*/
int main() {
int N;
cin >> N;
vector<long long> A(N), X(N), Y(N);
for (int i = 0; i < N; i++) cin >> A[i];
for (int i = 0; i < N; i++) cin >> X[i];
for (int i = 0; i < N; i++) cin >> Y[i];
auto func = [&](int i, int j) -> long long {
long long dx = abs(A[j-1] - X[i]), dy = abs(Y[i]);
return dx * dx * dx + dy * dy * dy;
};
DDMonotoneMinima<long long> opt;
auto res = opt.solve(N, func);
cout << res[N].first << endl;
}