Implementation of various algorithms
#define PROBLEM "https://atcoder.jp/contests/dp/tasks/dp_z"
#include "larsch.hpp"
// AtCoder EDPC Z - Frog 3
/*
H は単調増加数列
chmin(dp[j], dp[i] + (H[j] - H[i])^2 + C)
i -> j のコスト:(H[j] - H[i])^2 ...... 差の凸関数は Monge
スタート: 0, ゴール: N-1
*/
int main() {
long long N, C;
cin >> N >> C;
vector<long long> H(N);
for (long long i = 0; i < N; i++) cin >> H[i];
auto func = [&](int i, int j) -> long long {
return (H[j] - H[i]) * (H[j] - H[i]) + C;
};
LARSCH<long long> opt;
auto res = opt.solve(N-1, func);
cout << res[N-1].first << endl;
}#line 1 "tests/AtCoder/EDPC_Z_larsch.cpp"
#define PROBLEM "https://atcoder.jp/contests/dp/tasks/dp_z"
#line 2 "Optimization/larsch.hpp"
#include <bits/stdc++.h>
#line 4 "Optimization/larsch.hpp"
using namespace std;
// LARSCH, in O(N)
// vertex: 0, 1, 2, ..., N
// f(i, j) must be Monge (Then, A(j, i) = dp[i] + f(i, j) is also Monge)
template<class VAL, class FUNC> struct SubLARSCH {
struct RowReduce;
struct ColReduce;
struct ColMap {
const ColMap* parent = nullptr;
const vector<int> *v = nullptr;
constexpr int mapping(int i) const {
int x = (v ? (*v)[i] : i);
return (parent ? parent->mapping(x) : x);
}
};
struct Eval {
const FUNC *f = nullptr;
long long a = 1, b = 0; // row = a * i + b
const ColMap *cm = nullptr;
constexpr VAL operator () (int i, int j) const {
int i2 = int(a * i + b), j2 = (cm ? cm -> mapping(j) : j);
return (*f)(i2, j2);
}
};
struct RowReduce {
int N;
Eval e;
int cur_row = 0, state = 0;
unique_ptr<ColReduce> rec;
constexpr RowReduce(int N_, const Eval &e_) : N(N_), e(e_) {
int M = N / 2;
if (M > 0) {
Eval e2 = e;
e2.a = e.a * 2, e2.b = e.a + e.b;
rec = make_unique<ColReduce>(M, e2);
}
}
constexpr void reset() {
cur_row = 0, state = 0;
if (rec) rec->reset();
}
int get_argmin() {
int i = cur_row++;
if (!(i & 1)) {
int prev = state, next = (i + 1 == N ? N - 1 : rec->get_argmin());
state = next;
int res = prev;
for (int j = prev + 1; j <= next; j++) {
if (e(i, res) > e(i, j)) res = j;
}
return res;
} else {
return (e(i, state) <= e(i, i) ? state : i);
}
}
};
struct ColReduce {
int N;
Eval e;
int cur_row = 0;
vector<int> cols;
ColMap cm;
RowReduce rec;
constexpr ColReduce(int N_, const Eval &e_)
: N(N_), e(e_), cols(), cm{e.cm, &cols}, rec(N_, Eval{e.f, e.a, e.b, &cm}) {
cols.reserve(N);
}
constexpr void reset() {
cur_row = 0;
cols.clear();
rec.reset();
}
constexpr void push_col(int i, int j) {
while (!cols.empty()) {
int siz = (int)cols.size();
if (siz == i) break;
int last = cols.back();
if (e(siz - 1, last) > e(siz - 1, j)) cols.pop_back();
else break;
}
if ((int)cols.size() != N) cols.emplace_back(j);
}
constexpr int get_argmin() {
int i = cur_row++;
if (i == 0) {
cols.clear();
cols.emplace_back(0);
} else {
push_col(i, i * 2 - 1);
push_col(i, i * 2);
}
return cols[rec.get_argmin()];
}
};
FUNC f;
ColMap root_cm;
Eval root_eval;
unique_ptr<RowReduce> base;
explicit SubLARSCH(int N_, const FUNC &f_)
: f(std::move(f_)), root_cm{nullptr, nullptr}, root_eval{&f, 1, 0, &root_cm} {
base = make_unique<RowReduce>(N_, root_eval);
}
constexpr void reset() {
base->reset();
}
constexpr int get_argmin() {
return base->get_argmin();
}
};
template<class VAL> struct LARSCH {
VAL INF = numeric_limits<VAL>::max() / 2;
int CNT_INF = numeric_limits<int>::max() / 2;
// results
vector<VAL> dp;
vector<int> cnt, prev;
// solver
template<class FUNC> vector<pair<VAL, int>> solve(int N, const FUNC &f) {
dp.assign(N + 1, INF);
cnt.assign(N + 1, CNT_INF);
prev.assign(N + 1, 0);
vector<pair<VAL, int>> res(N + 1, make_pair(numeric_limits<VAL>::max() / 2, -1));
dp[0] = 0, cnt[0] = 0, res[0].first = 0;
auto f2 = [&](int i, int j) -> VAL {
i++;
if (i <= j) return INF;
else return dp[j] + f(j, i);
};
SubLARSCH<VAL, decltype(f2)> lar(N, f2);
for (int r = 1; r <= N; r++) {
int l = lar.get_argmin();
dp[r] = dp[l] + f(l, r);
prev[r] = l;
cnt[r] = cnt[l] + 1;
}
for (int r = 1; r <= N; r++) res[r] = {dp[r], prev[r]};
return res;
}
// reconstruct the shortest path
vector<int> reconstruct() {
int N = (int)dp.size() - 1;
vector<int> path;
for (int v = N; v > 0; v = prev[v]) path.emplace_back(v);
path.emplace_back(0);
reverse(path.begin(), path.end());
return path;
}
};
#line 4 "tests/AtCoder/EDPC_Z_larsch.cpp"
// AtCoder EDPC Z - Frog 3
/*
H は単調増加数列
chmin(dp[j], dp[i] + (H[j] - H[i])^2 + C)
i -> j のコスト:(H[j] - H[i])^2 ...... 差の凸関数は Monge
スタート: 0, ゴール: N-1
*/
int main() {
long long N, C;
cin >> N >> C;
vector<long long> H(N);
for (long long i = 0; i < N; i++) cin >> H[i];
auto func = [&](int i, int j) -> long long {
return (H[j] - H[i]) * (H[j] - H[i]) + C;
};
LARSCH<long long> opt;
auto res = opt.solve(N-1, func);
cout << res[N-1].first << endl;
}