Implementation of various algorithms
#include "Optimization/anti_monge_dd_smawk.hpp"分割統治 SMAWK 法を、anti-Monge 性を満たす単一始点最短路問題に適用したもの。
#pragma once
#include <bits/stdc++.h>
#include <cassert>
using namespace std;
#include "smawk.hpp"
// find shortest path on DAG with anti-Monge cost, by D&D SMAWK, O(NK log N)
// vertex: 0, 1, 2, ..., N
// f(i, j) must be anti-Monge in j >= i + K
// Then, A(j, i) = dp[i] + f(i, j) is also anti-Monge
// slide access NG
template<class VAL, class FUNC> vector<pair<VAL, int>> antiMongeDDSMAWK(int N, const FUNC &f, int K = 1) {
assert(K >= 1);
const VAL INF = numeric_limits<VAL>::max() / 4;
vector<pair<VAL, int>> res(N + 1, make_pair(INF, -1));
vector<pair<VAL, int>> tmp(N + 1, {INF, -1});
res[0].first = VAL(0);
auto relax = [&](int i, int j) -> void {
if (i != 0 && res[i].second == -1) return;
VAL val = res[i].first + f(i, j);
if (val < res[j].first) res[j] = {val, i};
};
auto rec = [&](auto &&rec, int left, int right) -> void {
if (right - left <= 1) return;
int mid = (left + right) / 2, border = min(right, mid + K - 1);
rec(rec, left, mid);
for (int j = mid; j < border; j++) {
for (int i = left; i < mid && i <= j - K; i++) relax(i, j);
}
if (border < right) {
vector<int> X, Y;
for (int j = border; j < right; j++) X.push_back(j);
for (int i = mid - 1; i >= left; i--) {
if (i == 0 || res[i].second != -1) Y.push_back(i);
}
if (!Y.empty()) {
vector<int> cols(Y.size());
iota(cols.begin(), cols.end(), 0);
auto f2 = [&](int j, int k) -> VAL { return res[Y[k]].first + f(Y[k], j); };
SMAWKRec(X, cols, f2, tmp);
for (auto x : X) {
if (tmp[x].first < res[x].first) res[x] = {tmp[x].first, Y[tmp[x].second]};
}
}
}
rec(rec, mid, right);
};
rec(rec, 0, N + 1);
return res;
}#line 2 "Optimization/anti_monge_dd_smawk.hpp"
#include <bits/stdc++.h>
#line 4 "Optimization/anti_monge_dd_smawk.hpp"
using namespace std;
#line 4 "Optimization/smawk.hpp"
using namespace std;
// find min_j f(i, j) for all i, by SMAWK, O(H + W)
// f(i, j) must be totally monotone
// slide access NG
template<class VAL, class FUNC> void SMAWKRec
(const vector<int> &X, const vector<int> &Y, const FUNC &f, vector<pair<VAL, int>> &res) {
if (X.empty()) return;
// Reduce Step
vector<int> X2, Y2;
for (auto y : Y) {
while (!Y2.empty()) {
int py = Y2.back(), x = X[(int)Y2.size() - 1];
if (f(x, y) >= f(x, py)) break;
Y2.pop_back();
}
if (Y2.size() < X.size()) Y2.emplace_back(y);
}
// Recurse Step
for (int i = 1; i < (int)X.size(); i += 2) X2.emplace_back(X[i]);
SMAWKRec(X2, Y2, f, res);
// Interpolate Step
int p = 0;
for (int i = 0; i < (int)X.size(); i += 2) {
int lim = (i + 1 < (int)X.size() ? res[X[i + 1]].second : Y.back()), best = Y[p];
while (Y[p] < lim) {
p++;
if (f(X[i], Y[p]) < f(X[i], best)) best = Y[p];
}
res[X[i]] = {f(X[i], best), best};
}
}
template<class VAL, class FUNC> vector<pair<VAL, int>> SMAWK(int H, int W, const FUNC &f) {
if (H == 0) return {};
assert(W > 0);
vector<pair<VAL, int>> res(H, make_pair(numeric_limits<VAL>::max() / 2, -1));
vector<int> X(H), Y(W);
for (int i = 0; i < H; i++) X[i] = i;
for (int j = 0; j < W; j++) Y[j] = j;
SMAWKRec(X, Y, f, res);
return res;
}
#line 7 "Optimization/anti_monge_dd_smawk.hpp"
// find shortest path on DAG with anti-Monge cost, by D&D SMAWK, O(NK log N)
// vertex: 0, 1, 2, ..., N
// f(i, j) must be anti-Monge in j >= i + K
// Then, A(j, i) = dp[i] + f(i, j) is also anti-Monge
// slide access NG
template<class VAL, class FUNC> vector<pair<VAL, int>> antiMongeDDSMAWK(int N, const FUNC &f, int K = 1) {
assert(K >= 1);
const VAL INF = numeric_limits<VAL>::max() / 4;
vector<pair<VAL, int>> res(N + 1, make_pair(INF, -1));
vector<pair<VAL, int>> tmp(N + 1, {INF, -1});
res[0].first = VAL(0);
auto relax = [&](int i, int j) -> void {
if (i != 0 && res[i].second == -1) return;
VAL val = res[i].first + f(i, j);
if (val < res[j].first) res[j] = {val, i};
};
auto rec = [&](auto &&rec, int left, int right) -> void {
if (right - left <= 1) return;
int mid = (left + right) / 2, border = min(right, mid + K - 1);
rec(rec, left, mid);
for (int j = mid; j < border; j++) {
for (int i = left; i < mid && i <= j - K; i++) relax(i, j);
}
if (border < right) {
vector<int> X, Y;
for (int j = border; j < right; j++) X.push_back(j);
for (int i = mid - 1; i >= left; i--) {
if (i == 0 || res[i].second != -1) Y.push_back(i);
}
if (!Y.empty()) {
vector<int> cols(Y.size());
iota(cols.begin(), cols.end(), 0);
auto f2 = [&](int j, int k) -> VAL { return res[Y[k]].first + f(Y[k], j); };
SMAWKRec(X, cols, f2, tmp);
for (auto x : X) {
if (tmp[x].first < res[x].first) res[x] = {tmp[x].first, Y[tmp[x].second]};
}
}
}
rec(rec, mid, right);
};
rec(rec, 0, N + 1);
return res;
}